START Program.exe works, START path\Program.exe fails
Posted: 2021-Nov-08, 5:55 am
I use a program called Internet Download Accelerator. The main executable is named "ida.exe". It's installed in;
c:\Program Files\Internet Download Accelerator\
It can be called from the command line, but for some reason, it doesn't seem to act like other programs.
This works;
But ties up the script until the program is closed.
This also works;
The program is started as a separate process and the script is free to continue.
However this does NOT work;
The program never opens.
Am I doing something wrong? I was under the impression that using the start command to start a program would be 100% identical to just typing its name, only that it would be started in a separate process. It's worked with every other program I've used it on, but it doesn't work with this one.
It works if you just type the path and the name, it works if you CD to the directory and start the program, but you can't run it with start and the path\name.
c:\Program Files\Internet Download Accelerator\
It can be called from the command line, but for some reason, it doesn't seem to act like other programs.
This works;
Code: Select all
"C:\Program Files\Internet Download Accelerator\ida.exe" %URL%
This also works;
Code: Select all
cd /d "C:\Program Files\Internet Download Accelerator\"
start ida.exe %URL%
However this does NOT work;
Code: Select all
start "c:\Program Files\Internet Download Accelerator\ida.exe" %URL%
Am I doing something wrong? I was under the impression that using the start command to start a program would be 100% identical to just typing its name, only that it would be started in a separate process. It's worked with every other program I've used it on, but it doesn't work with this one.
It works if you just type the path and the name, it works if you CD to the directory and start the program, but you can't run it with start and the path\name.