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I got a hand writing this code from someone on here awhile back which turned out to work just as i wanted, now a new problem has came to my attention this program will tell the user how many environment variables start with the letter they input, now what is i want them to be able to put in more then one letter separated by a space and it will tell them how many start with all, lets say 5 letters total?
SETLOCAL
SET /p "letter=Choose a letter "
if "%letter%" == "" (
echo Usage: Please enter a letter!
pause
exit /b 1
)
SET "letter=%letter:~0,1%"
FOR /f %%a IN ('2^>nul set %letter% ^|find /c "=" ' ) DO SET count=%%a
shift /1
ECHO %count% variables START "%letter%"
pause
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I modified your code - test it to see how it goes.
@echo off
SETLOCAL
:begin
SET /p "letter=Choose a letter "
if "%letter%" == "" (
echo Usage: Please enter a letter!
pause
cls
goto :begin
)
for %%a in (%letter%) do call :routine %%a
pause
goto :eof
:routine
set letter2=%1
FOR /f %%a IN ('2^>nul set "%letter2:~0,1%" ^|find /c "=" ' ) do ECHO %%a variables START with "%letter2:~0,1%"Offline
I modified your code - test it to see how it goes.
@echo off SETLOCAL :begin SET /p "letter=Choose a letter " if "%letter%" == "" ( echo Usage: Please enter a letter! pause cls goto :begin ) for %%a in (%letter%) do call :routine %%a pause goto :eof :routine set letter2=%1 FOR /f %%a IN ('2^>nul set "%letter2:~0,1%" ^|find /c "=" ' ) do ECHO %%a variables START with "%letter2:~0,1%"
Thanks, if you have the time would you be able to explain how your for loop that you added works?
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Put an echo keyword before the call keyword and run it.
It should give you a clue as to how it works.
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